1/**
2 * eCryptfs: Linux filesystem encryption layer
3 * Functions only useful for debugging.
4 *
5 * Copyright (C) 2006 International Business Machines Corp.
6 *   Author(s): Michael A. Halcrow <mahalcro@us.ibm.com>
7 *
8 * This program is free software; you can redistribute it and/or
9 * modify it under the terms of the GNU General Public License as
10 * published by the Free Software Foundation; either version 2 of the
11 * License, or (at your option) any later version.
12 *
13 * This program is distributed in the hope that it will be useful, but
14 * WITHOUT ANY WARRANTY; without even the implied warranty of
15 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
16 * General Public License for more details.
17 *
18 * You should have received a copy of the GNU General Public License
19 * along with this program; if not, write to the Free Software
20 * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA
21 * 02111-1307, USA.
22 */
23
24#include "ecryptfs_kernel.h"
25
26/**
27 * ecryptfs_dump_auth_tok - debug function to print auth toks
28 *
29 * This function will print the contents of an ecryptfs authentication
30 * token.
31 */
32void ecryptfs_dump_auth_tok(struct ecryptfs_auth_tok *auth_tok)
33{
34	char salt[ECRYPTFS_SALT_SIZE * 2 + 1];
35	char sig[ECRYPTFS_SIG_SIZE_HEX + 1];
36
37	ecryptfs_printk(KERN_DEBUG, "Auth tok at mem loc [%p]:\n",
38			auth_tok);
39	if (auth_tok->flags & ECRYPTFS_PRIVATE_KEY) {
40		ecryptfs_printk(KERN_DEBUG, " * private key type\n");
41	} else {
42		ecryptfs_printk(KERN_DEBUG, " * passphrase type\n");
43		ecryptfs_to_hex(salt, auth_tok->token.password.salt,
44				ECRYPTFS_SALT_SIZE);
45		salt[ECRYPTFS_SALT_SIZE * 2] = '\0';
46		ecryptfs_printk(KERN_DEBUG, " * salt = [%s]\n", salt);
47		if (auth_tok->token.password.flags &
48		    ECRYPTFS_PERSISTENT_PASSWORD) {
49			ecryptfs_printk(KERN_DEBUG, " * persistent\n");
50		}
51		memcpy(sig, auth_tok->token.password.signature,
52		       ECRYPTFS_SIG_SIZE_HEX);
53		sig[ECRYPTFS_SIG_SIZE_HEX] = '\0';
54		ecryptfs_printk(KERN_DEBUG, " * signature = [%s]\n", sig);
55	}
56	ecryptfs_printk(KERN_DEBUG, " * session_key.flags = [0x%x]\n",
57			auth_tok->session_key.flags);
58	if (auth_tok->session_key.flags
59	    & ECRYPTFS_USERSPACE_SHOULD_TRY_TO_DECRYPT)
60		ecryptfs_printk(KERN_DEBUG,
61				" * Userspace decrypt request set\n");
62	if (auth_tok->session_key.flags
63	    & ECRYPTFS_USERSPACE_SHOULD_TRY_TO_ENCRYPT)
64		ecryptfs_printk(KERN_DEBUG,
65				" * Userspace encrypt request set\n");
66	if (auth_tok->session_key.flags & ECRYPTFS_CONTAINS_DECRYPTED_KEY) {
67		ecryptfs_printk(KERN_DEBUG, " * Contains decrypted key\n");
68		ecryptfs_printk(KERN_DEBUG,
69				" * session_key.decrypted_key_size = [0x%x]\n",
70				auth_tok->session_key.decrypted_key_size);
71		ecryptfs_printk(KERN_DEBUG, " * Decrypted session key "
72				"dump:\n");
73		if (ecryptfs_verbosity > 0)
74			ecryptfs_dump_hex(auth_tok->session_key.decrypted_key,
75					  ECRYPTFS_DEFAULT_KEY_BYTES);
76	}
77	if (auth_tok->session_key.flags & ECRYPTFS_CONTAINS_ENCRYPTED_KEY) {
78		ecryptfs_printk(KERN_DEBUG, " * Contains encrypted key\n");
79		ecryptfs_printk(KERN_DEBUG,
80				" * session_key.encrypted_key_size = [0x%x]\n",
81				auth_tok->session_key.encrypted_key_size);
82		ecryptfs_printk(KERN_DEBUG, " * Encrypted session key "
83				"dump:\n");
84		if (ecryptfs_verbosity > 0)
85			ecryptfs_dump_hex(auth_tok->session_key.encrypted_key,
86					  auth_tok->session_key.
87					  encrypted_key_size);
88	}
89}
90
91/**
92 * ecryptfs_dump_hex - debug hex printer
93 * @data: string of bytes to be printed
94 * @bytes: number of bytes to print
95 *
96 * Dump hexadecimal representation of char array
97 */
98void ecryptfs_dump_hex(char *data, int bytes)
99{
100	int i = 0;
101	int add_newline = 1;
102
103	if (ecryptfs_verbosity < 1)
104		return;
105	if (bytes != 0) {
106		printk(KERN_DEBUG "0x%.2x.", (unsigned char)data[i]);
107		i++;
108	}
109	while (i < bytes) {
110		printk("0x%.2x.", (unsigned char)data[i]);
111		i++;
112		if (i % 16 == 0) {
113			printk("\n");
114			add_newline = 0;
115		} else
116			add_newline = 1;
117	}
118	if (add_newline)
119		printk("\n");
120}
121
122