1PROPER CARE AND FEEDING OF RETURN VALUES FROM rcu_dereference()
2
3Most of the time, you can use values from rcu_dereference() or one of
4the similar primitives without worries.  Dereferencing (prefix "*"),
5field selection ("->"), assignment ("="), address-of ("&"), addition and
6subtraction of constants, and casts all work quite naturally and safely.
7
8It is nevertheless possible to get into trouble with other operations.
9Follow these rules to keep your RCU code working properly:
10
11o	You must use one of the rcu_dereference() family of primitives
12	to load an RCU-protected pointer, otherwise CONFIG_PROVE_RCU
13	will complain.  Worse yet, your code can see random memory-corruption
14	bugs due to games that compilers and DEC Alpha can play.
15	Without one of the rcu_dereference() primitives, compilers
16	can reload the value, and won't your code have fun with two
17	different values for a single pointer!  Without rcu_dereference(),
18	DEC Alpha can load a pointer, dereference that pointer, and
19	return data preceding initialization that preceded the store of
20	the pointer.
21
22	In addition, the volatile cast in rcu_dereference() prevents the
23	compiler from deducing the resulting pointer value.  Please see
24	the section entitled "EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH"
25	for an example where the compiler can in fact deduce the exact
26	value of the pointer, and thus cause misordering.
27
28o	Avoid cancellation when using the "+" and "-" infix arithmetic
29	operators.  For example, for a given variable "x", avoid
30	"(x-x)".  There are similar arithmetic pitfalls from other
31	arithmetic operators, such as "(x*0)", "(x/(x+1))" or "(x%1)".
32	The compiler is within its rights to substitute zero for all of
33	these expressions, so that subsequent accesses no longer depend
34	on the rcu_dereference(), again possibly resulting in bugs due
35	to misordering.
36
37	Of course, if "p" is a pointer from rcu_dereference(), and "a"
38	and "b" are integers that happen to be equal, the expression
39	"p+a-b" is safe because its value still necessarily depends on
40	the rcu_dereference(), thus maintaining proper ordering.
41
42o	Avoid all-zero operands to the bitwise "&" operator, and
43	similarly avoid all-ones operands to the bitwise "|" operator.
44	If the compiler is able to deduce the value of such operands,
45	it is within its rights to substitute the corresponding constant
46	for the bitwise operation.  Once again, this causes subsequent
47	accesses to no longer depend on the rcu_dereference(), causing
48	bugs due to misordering.
49
50	Please note that single-bit operands to bitwise "&" can also
51	be dangerous.  At this point, the compiler knows that the
52	resulting value can only take on one of two possible values.
53	Therefore, a very small amount of additional information will
54	allow the compiler to deduce the exact value, which again can
55	result in misordering.
56
57o	If you are using RCU to protect JITed functions, so that the
58	"()" function-invocation operator is applied to a value obtained
59	(directly or indirectly) from rcu_dereference(), you may need to
60	interact directly with the hardware to flush instruction caches.
61	This issue arises on some systems when a newly JITed function is
62	using the same memory that was used by an earlier JITed function.
63
64o	Do not use the results from the boolean "&&" and "||" when
65	dereferencing.	For example, the following (rather improbable)
66	code is buggy:
67
68		int *p;
69		int *q;
70
71		...
72
73		p = rcu_dereference(gp)
74		q = &global_q;
75		q += p != &oom_p1 && p != &oom_p2;
76		r1 = *q;  /* BUGGY!!! */
77
78	The reason this is buggy is that "&&" and "||" are often compiled
79	using branches.  While weak-memory machines such as ARM or PowerPC
80	do order stores after such branches, they can speculate loads,
81	which can result in misordering bugs.
82
83o	Do not use the results from relational operators ("==", "!=",
84	">", ">=", "<", or "<=") when dereferencing.  For example,
85	the following (quite strange) code is buggy:
86
87		int *p;
88		int *q;
89
90		...
91
92		p = rcu_dereference(gp)
93		q = &global_q;
94		q += p > &oom_p;
95		r1 = *q;  /* BUGGY!!! */
96
97	As before, the reason this is buggy is that relational operators
98	are often compiled using branches.  And as before, although
99	weak-memory machines such as ARM or PowerPC do order stores
100	after such branches, but can speculate loads, which can again
101	result in misordering bugs.
102
103o	Be very careful about comparing pointers obtained from
104	rcu_dereference() against non-NULL values.  As Linus Torvalds
105	explained, if the two pointers are equal, the compiler could
106	substitute the pointer you are comparing against for the pointer
107	obtained from rcu_dereference().  For example:
108
109		p = rcu_dereference(gp);
110		if (p == &default_struct)
111			do_default(p->a);
112
113	Because the compiler now knows that the value of "p" is exactly
114	the address of the variable "default_struct", it is free to
115	transform this code into the following:
116
117		p = rcu_dereference(gp);
118		if (p == &default_struct)
119			do_default(default_struct.a);
120
121	On ARM and Power hardware, the load from "default_struct.a"
122	can now be speculated, such that it might happen before the
123	rcu_dereference().  This could result in bugs due to misordering.
124
125	However, comparisons are OK in the following cases:
126
127	o	The comparison was against the NULL pointer.  If the
128		compiler knows that the pointer is NULL, you had better
129		not be dereferencing it anyway.  If the comparison is
130		non-equal, the compiler is none the wiser.  Therefore,
131		it is safe to compare pointers from rcu_dereference()
132		against NULL pointers.
133
134	o	The pointer is never dereferenced after being compared.
135		Since there are no subsequent dereferences, the compiler
136		cannot use anything it learned from the comparison
137		to reorder the non-existent subsequent dereferences.
138		This sort of comparison occurs frequently when scanning
139		RCU-protected circular linked lists.
140
141	o	The comparison is against a pointer that references memory
142		that was initialized "a long time ago."  The reason
143		this is safe is that even if misordering occurs, the
144		misordering will not affect the accesses that follow
145		the comparison.  So exactly how long ago is "a long
146		time ago"?  Here are some possibilities:
147
148		o	Compile time.
149
150		o	Boot time.
151
152		o	Module-init time for module code.
153
154		o	Prior to kthread creation for kthread code.
155
156		o	During some prior acquisition of the lock that
157			we now hold.
158
159		o	Before mod_timer() time for a timer handler.
160
161		There are many other possibilities involving the Linux
162		kernel's wide array of primitives that cause code to
163		be invoked at a later time.
164
165	o	The pointer being compared against also came from
166		rcu_dereference().  In this case, both pointers depend
167		on one rcu_dereference() or another, so you get proper
168		ordering either way.
169
170		That said, this situation can make certain RCU usage
171		bugs more likely to happen.  Which can be a good thing,
172		at least if they happen during testing.  An example
173		of such an RCU usage bug is shown in the section titled
174		"EXAMPLE OF AMPLIFIED RCU-USAGE BUG".
175
176	o	All of the accesses following the comparison are stores,
177		so that a control dependency preserves the needed ordering.
178		That said, it is easy to get control dependencies wrong.
179		Please see the "CONTROL DEPENDENCIES" section of
180		Documentation/memory-barriers.txt for more details.
181
182	o	The pointers are not equal -and- the compiler does
183		not have enough information to deduce the value of the
184		pointer.  Note that the volatile cast in rcu_dereference()
185		will normally prevent the compiler from knowing too much.
186
187		However, please note that if the compiler knows that the
188		pointer takes on only one of two values, a not-equal
189		comparison will provide exactly the information that the
190		compiler needs to deduce the value of the pointer.
191
192o	Disable any value-speculation optimizations that your compiler
193	might provide, especially if you are making use of feedback-based
194	optimizations that take data collected from prior runs.  Such
195	value-speculation optimizations reorder operations by design.
196
197	There is one exception to this rule:  Value-speculation
198	optimizations that leverage the branch-prediction hardware are
199	safe on strongly ordered systems (such as x86), but not on weakly
200	ordered systems (such as ARM or Power).  Choose your compiler
201	command-line options wisely!
202
203
204EXAMPLE OF AMPLIFIED RCU-USAGE BUG
205
206Because updaters can run concurrently with RCU readers, RCU readers can
207see stale and/or inconsistent values.  If RCU readers need fresh or
208consistent values, which they sometimes do, they need to take proper
209precautions.  To see this, consider the following code fragment:
210
211	struct foo {
212		int a;
213		int b;
214		int c;
215	};
216	struct foo *gp1;
217	struct foo *gp2;
218
219	void updater(void)
220	{
221		struct foo *p;
222
223		p = kmalloc(...);
224		if (p == NULL)
225			deal_with_it();
226		p->a = 42;  /* Each field in its own cache line. */
227		p->b = 43;
228		p->c = 44;
229		rcu_assign_pointer(gp1, p);
230		p->b = 143;
231		p->c = 144;
232		rcu_assign_pointer(gp2, p);
233	}
234
235	void reader(void)
236	{
237		struct foo *p;
238		struct foo *q;
239		int r1, r2;
240
241		p = rcu_dereference(gp2);
242		if (p == NULL)
243			return;
244		r1 = p->b;  /* Guaranteed to get 143. */
245		q = rcu_dereference(gp1);  /* Guaranteed non-NULL. */
246		if (p == q) {
247			/* The compiler decides that q->c is same as p->c. */
248			r2 = p->c; /* Could get 44 on weakly order system. */
249		}
250		do_something_with(r1, r2);
251	}
252
253You might be surprised that the outcome (r1 == 143 && r2 == 44) is possible,
254but you should not be.  After all, the updater might have been invoked
255a second time between the time reader() loaded into "r1" and the time
256that it loaded into "r2".  The fact that this same result can occur due
257to some reordering from the compiler and CPUs is beside the point.
258
259But suppose that the reader needs a consistent view?
260
261Then one approach is to use locking, for example, as follows:
262
263	struct foo {
264		int a;
265		int b;
266		int c;
267		spinlock_t lock;
268	};
269	struct foo *gp1;
270	struct foo *gp2;
271
272	void updater(void)
273	{
274		struct foo *p;
275
276		p = kmalloc(...);
277		if (p == NULL)
278			deal_with_it();
279		spin_lock(&p->lock);
280		p->a = 42;  /* Each field in its own cache line. */
281		p->b = 43;
282		p->c = 44;
283		spin_unlock(&p->lock);
284		rcu_assign_pointer(gp1, p);
285		spin_lock(&p->lock);
286		p->b = 143;
287		p->c = 144;
288		spin_unlock(&p->lock);
289		rcu_assign_pointer(gp2, p);
290	}
291
292	void reader(void)
293	{
294		struct foo *p;
295		struct foo *q;
296		int r1, r2;
297
298		p = rcu_dereference(gp2);
299		if (p == NULL)
300			return;
301		spin_lock(&p->lock);
302		r1 = p->b;  /* Guaranteed to get 143. */
303		q = rcu_dereference(gp1);  /* Guaranteed non-NULL. */
304		if (p == q) {
305			/* The compiler decides that q->c is same as p->c. */
306			r2 = p->c; /* Locking guarantees r2 == 144. */
307		}
308		spin_unlock(&p->lock);
309		do_something_with(r1, r2);
310	}
311
312As always, use the right tool for the job!
313
314
315EXAMPLE WHERE THE COMPILER KNOWS TOO MUCH
316
317If a pointer obtained from rcu_dereference() compares not-equal to some
318other pointer, the compiler normally has no clue what the value of the
319first pointer might be.  This lack of knowledge prevents the compiler
320from carrying out optimizations that otherwise might destroy the ordering
321guarantees that RCU depends on.  And the volatile cast in rcu_dereference()
322should prevent the compiler from guessing the value.
323
324But without rcu_dereference(), the compiler knows more than you might
325expect.  Consider the following code fragment:
326
327	struct foo {
328		int a;
329		int b;
330	};
331	static struct foo variable1;
332	static struct foo variable2;
333	static struct foo *gp = &variable1;
334
335	void updater(void)
336	{
337		initialize_foo(&variable2);
338		rcu_assign_pointer(gp, &variable2);
339		/*
340		 * The above is the only store to gp in this translation unit,
341		 * and the address of gp is not exported in any way.
342		 */
343	}
344
345	int reader(void)
346	{
347		struct foo *p;
348
349		p = gp;
350		barrier();
351		if (p == &variable1)
352			return p->a; /* Must be variable1.a. */
353		else
354			return p->b; /* Must be variable2.b. */
355	}
356
357Because the compiler can see all stores to "gp", it knows that the only
358possible values of "gp" are "variable1" on the one hand and "variable2"
359on the other.  The comparison in reader() therefore tells the compiler
360the exact value of "p" even in the not-equals case.  This allows the
361compiler to make the return values independent of the load from "gp",
362in turn destroying the ordering between this load and the loads of the
363return values.  This can result in "p->b" returning pre-initialization
364garbage values.
365
366In short, rcu_dereference() is -not- optional when you are going to
367dereference the resulting pointer.
368