Searched refs:Kb (Results 1 – 12 of 12) sorted by relevance
6 bool "Use 16Kb for kernel stacks instead of 8Kb"8 If you say Y here the kernel will use a 16Kb stacksize for the
14 #define Kb (1024) macro15 #define Mb (Kb*Kb)
10 bool "Use 4Kb for kernel stacks instead of 8Kb"13 If you say Y here the kernel will use a 4Kb stacksize for the
32 bool "Use 4Kb for kernel stacks instead of 8Kb"35 If you say Y here the kernel will use a 4Kb stacksize for the
791 k = memsize * Kb; in get_memsize()795 k = 2560 * Kb; in get_memsize()802 k = 512 * Kb; in get_memsize()859 k -= memdiff * Kb; in get_memsize()860 output("framebuffer size = %d Kb\n", k / Kb); in get_memsize()
316 bool "Use 4Kb for kernel stacks instead of 8Kb"319 If you say Y here the kernel will use a 4Kb stacksize for the
48 # the same 8Kb page, so that break.S can be more efficient when performing
94 here the DMA buffers (64Kb) will be allocated at boot time and kept
471 able to data at over 48Kb/s [ISDN link -Simon]. I managed a
268 here the DMA buffers (64Kb) will be allocated at boot time and kept
445 more memory. Each concurrent packet will require approximately 64Kb
1803 block is 1 page, not 1Kb minix block.1887 for blocksizes of up to 4Kb.