Searched refs:p_idx_max2 (Results 1 – 1 of 1) sorted by relevance
176 int p_idx_max1, p_idx_max2; in enc_pools_release_free_pages() local183 p_idx_max2 = (page_pools.epp_total_pages - 1) / PAGES_PER_POOL; in enc_pools_release_free_pages()210 while (p_idx_max1 < p_idx_max2) { in enc_pools_release_free_pages()211 LASSERT(page_pools.epp_pools[p_idx_max2]); in enc_pools_release_free_pages()212 kfree(page_pools.epp_pools[p_idx_max2]); in enc_pools_release_free_pages()213 page_pools.epp_pools[p_idx_max2] = NULL; in enc_pools_release_free_pages()214 p_idx_max2--; in enc_pools_release_free_pages()