Searched refs:p_idx_max1 (Results 1 – 1 of 1) sorted by relevance
176 int p_idx_max1, p_idx_max2; in enc_pools_release_free_pages() local189 p_idx_max1 = page_pools.epp_total_pages == 0 ? -1 : in enc_pools_release_free_pages()210 while (p_idx_max1 < p_idx_max2) { in enc_pools_release_free_pages()