Lines Matching refs:inexact
971 # and inexact. and, the inexact is such that overflow occurred and was disabled
972 # but inexact was enabled.
1365 btst &inex2_bit,FPCR_ENABLE(%a6) # was inexact enabled?
1389 # the enabled exception was inexact
1943 btst &inex2_bit,FPCR_ENABLE(%a6) # was inexact enabled?
1967 # the enabled exception was inexact
4204 # the enabled exception was inexact. so, if it occurs with an overflow
6770 #Returns PI and inexact exception
6972 # with an inexact result. Thus, 9.5 always raises the #
6973 # inexact together with either overflow or underflow. #
7073 # straightforward 8.2 generates the inexact exception as #
7103 # Notes: 10.2 will always create an inexact and return -1 + tiny #
10163 # inexact is enabled. #
10270 # the inexact bits if the number is inexact for the #
10286 # result would be inexact for the given precision. make a copy of the
11653 # set the inexact bits.
11655 # - if overflow or inexact is enabled, we need a multiply result rounded to
11764 # set the inexact bits.
11766 # - if overflow or inexact is enabled, we need a multiply result rounded to
13599 # if underflow or inexact is enabled, go calculate EXOP first.
15679 # if underflow or inexact is enabled, go calculate EXOP first.