Lines Matching refs:all

14 carefully, leaving an old version of the data structure in place until all
19 How can an RCU writer possibly determine when all readers are finished,
21 presence? There is a synchronize_rcu() primitive that blocks until all
74 a grace period to elapse, rcu_barrier() waits for all outstanding RCU
153 52   /* Wait for all RCU callbacks to fire. */
172 Lines 7-50 stop all the kernel tasks associated with the rcutorture
184 module invokes call_rcu() from timers, you will need to first cancel all
201 callback queues, and then waits until they have all started executing, at
202 which point, all earlier RCU callbacks are guaranteed to have completed.
223 ensures that all the calls to rcu_barrier_func() will have completed
311 	means that all CPUs have executed rcu_barrier_func() before